Area of the quadrilaterals formed by drawing tangents at the ends of latus recta of $\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1$ is
Area of the quadrilaterals formed by drawing tangents at the ends of latus recta of $\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1$ is
- A
$\frac{{16}}{{\sqrt 3 }}$
- B
$\frac{{8}}{{\sqrt 3 }}$
- C
$\frac{{4}}{{\sqrt 3 }}$
- D
$4\sqrt 3 $
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- [JEE MAIN 2020]
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